c# SmtpClient e-posta kaynak kodunu gönderiyor

Küçük · Yayınlandı 25.12.2015 12:46:03

/// <summary>
/// 处审核后类的实例
/// </summary>
/// <param name="To">收件人地址集合</param> 根据个人需要是单个收件人或者多个
/// <param name="Body">邮件正文</param>
/// <param name="Title">邮件的主题</param>
public SendMail(List<string> To, string Body, string Title)
{
mailMessage = new MailMessage();
foreach (string str in To)
{
mailMessage.To.Add(str);
}
List<sendmailinfoModel> list = new List<sendmailinfoModel>();
sendmailinfoProc sendMailinfoProc = new sendmailinfoProc();
list = sendMailinfoProc.GetList(null);
sendmailinfoModel sendinfo = list[0] as sendmailinfoModel;
if (sendinfo != null)
{
mailMessage.From = new System.Net.Mail.MailAddress(sendinfo.Mailaddress, sendinfo.Mailname);
//mailMessage.From = new System.Net.Mail.MailAddress("aaa@163.com");
mailMessage.Subject = Title;
mailMessage.Body = Body;
mailMessage.IsBodyHtml = false;
mailMessage.BodyEncoding = System.Text.Encoding.UTF8;
mailMessage.Priority = System.Net.Mail.MailPriority.Normal;
this.password = sendinfo.Mailpassword;
//this.password = "***";
smtpserver = sendinfo.Smtpserver;
}
}
/// <summary>
/// 发送邮件
/// </summary>
public SmtpStatusCode Send()
{
if (mailMessage != null)
{
smtpClient = new SmtpClient();
smtpClient.Credentials = new System.Net.NetworkCredential(mailMessage.From.Address, password);//设置发件人身份的票据
smtpClient.DeliveryMethod = System.Net.Mail.SmtpDeliveryMethod.Network;
smtpClient.Host = smtpserver;
try
{
smtpClient.Send(mailMessage);
}
catch (SmtpException e)
{
return e.StatusCode;
}
return SmtpStatusCode.Ok;
}
return SmtpStatusCode.SyntaxError;
}

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[Kaynak] c# SmtpClient e-posta kaynak kodunu gönderiyor

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