linq deleguoja SQL sakinio sujungimą

Mažai purvo · Paskelbta 2015-08-05 10:35:47

/// <summary>
/// 请假数据
/// </summary>
/// <param name="ApplyUser">用户ID</param>
/// <param name="title">标题</param>
/// <param name="startTime">开始时间</param>
/// <param name="EndTime">结束时间</param>
/// <param name="Status">状态</param>
/// <param name="ye">分页</param>
/// <returns></returns>
public static List<Model.ViewApprove> GetApprove(string ApplyUser,string title,DateTime? startTime,DateTime? EndTime,byte Status, int ye)
{
bool tag=true;
Func<Model.ViewApprove,bool> fwhere = m =>
{
tag = tag && m.ApplyUser == ApplyUser;
if (title != ""&&title!=null)
tag=tag&&m.Title.Contains(title);
if (startTime!=null)
tag = tag && m.ApplyDate >= startTime;
if (EndTime != null)
tag = tag && m.ApplyDate <= EndTime;
if (Status != null)
tag = tag && m.Status == Status;
return tag;
};
return db.ViewApprove.Where(fwhere).Skip(ye).Take(10).ToList();
}

Kopijuoti kodą

Mažai purvo · Paskelbta 2015-08-07 10:43:16

Aukščiau yra klaidų, o teisingos yra šios:

/// <summary>
/// 请假数据
/// </summary>
/// <param name="ApplyUser">用户ID</param>
/// <param name="title">标题</param>
/// <param name="startTime">开始时间</param>
/// <param name="EndTime">结束时间</param>
/// <param name="Status">状态</param>
/// <param name="ye">分页</param>
/// <returns></returns>
public static List<Model.ViewApprove> GetApprove(string ApplyUser,string title,DateTime? startTime,DateTime? EndTime,byte Status, int ye)
{
Func<Model.ViewApprove,bool> fwhere = m =>
{
bool cktitle = true;
bool ckstartTime = true;
bool ckEndTime = true;
bool ckStatus = true;
if (title != ""&&title!=null)
cktitle = m.Title.Contains(title);
if (startTime!=null)
ckstartTime = m.ApplyDate >= startTime;
if (EndTime != null)
ckEndTime = m.ApplyDate <= EndTime;
if (Status != 2)
ckStatus = m.Status == Status;
return m.ApplyUser == ApplyUser && cktitle && ckstartTime && ckStatus;
};
return db.ViewApprove.Where(fwhere).Skip(ye).Take(10).ToList();
}

Kopijuoti kodą

[Šaltinis] linq deleguoja SQL sakinio sujungimą