//数组a中n个整数按相反的顺序存放
Use a function INV to implement it, the actual parameter uses the array name a, and the shape parameter can also use the array name or pointer variable
#include "stdafx.h"
#include "stdio.h"
int main(int argc, char* argv[])
{void inv(int x[],int n); inv function
int i,a[10]={3,7,9,11,0,6,7,5,4,2};
printf("the original array:\n");
for(i=0; i<10; i++)
printf("%d,",a[i]);
printf("\n");
inv(a,10);
printf("the array has been inverted:\n");
for(i=0; i<10; i++)
printf("%d,",a[i]);
printf("\n");
return 0;
}
void inv(int x[],int n)
{int temp,i,j,m=(n-1)/2;
for(i=0; i<=m; i++)
{j=n-1-i;
temp=x[i]; x[i]=x[j]; x[j]=temp;
}
return;
}
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Posted on 12/10/2015 5:17:11 PM
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